C++ Linear Equation

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C++ Linear Equation

Postby Thor » Fri Apr 04, 2014 12:32 pm

Alright, im trying to wrap my head around something here, perhaps I need more coffee. I've recently completed a simple programming challenge, but upon completion I see that some other entries are different from what I submitted.

The challenge description is here: http://www.talentbuddy.co/challenge/528 ... 0af383a409.

So, given the values for 'a' and 'b' , we need to complete a function that solves for x in this equation: a*x + b = 0. If any value of x satisfies the equation please print "INF" (infinium).

A lot of solutions are like so:
Code: Select all
#include <iostream> using namespace std; void solve_equation(double a, double b) { if(a==0) cout << "INF"; else cout << -b/a; }
My solution will print "INF" is either 'a' or 'b' input is 0. Which is more correct? What aren't some people checking for what 'b' is then making 'b' negative? My code covers more situations, but apparently just a few lines is all that is needed.
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Re: C++ Linear Equation

Postby Cool_Fire » Sat Apr 05, 2014 6:57 am

If a = 0 then b must = 0 too for the whole thing to = 0 so you can skip the check since you're sure this is a condition that cannot happen. This is something you can do in math but I wouldn't recommend it in real world programming.
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Re: C++ Linear Equation

Postby Thor » Sun Apr 06, 2014 9:24 pm

If a = 0 then b must = 0 too for the whole thing to = 0 so you can skip the check since you're sure this is a condition that cannot happen. This is something you can do in math but I wouldn't recommend it in real world programming.
I see what you are saying. For whatever reason, this wasn't apparent to me at first. What the other coders were doing was coding for this specific situation where the equation equaled 0 every time, allowing for the 'shortcut'. I went ahead and coded to solve every possible situation I could think of whether the equation ended in zero or not. Perhaps too much coffee was what the real issue actually was.
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